Thread: Random Word Generator? Plz Help

OK, so I would much appreciate anybodys help with this problem.

I have to come up with a program that will generate 1000 random words. These words don't have to be actual words in the dictionary, just a series of character. The words can be no longer than 9 characters. This is what I have so far....

Code:

#include <stdio.h>

int main() {
int i, j;
char temp[9];

for(i=0; i<1000; i++) {
int run=rand()%7 + 3;
for(j=0; j< run ; j++){
temp[j]= rand()%26+'a';
}
temp[run] = '\0';
printf("%s\n\n",temp);
}


system("PAUSE");
return

The first problem is that some of the words are more than 9 characters, and then the program only prints like 100 words not 1000. Any help or explanation would be great. Thanks in advanced.

Try char temp[10]; You need an extra character for the trailing null when the length is 9 characters.

Thanks You, that fixed the number of character problems. It is still not printing out 1000 words though...Any ideas?

Code:

#include <stdio.h>

int main(void)  
{
int i, j, run;
char temp[9];

for(i=0; i<1000; i++) 
  { run=rand()%7 + 3;
    for(j=0; j< run ; j++)
      { temp[j]= rand()%26+'a'; }
    temp[run] = '\0';
    printf("%d %s\n",i + 1,temp); }


return 0;
}

Yes it does print a thousand words...

Ok, that's strange. When I compile the code it only shows words 702-1000, on the actually screen...is there just something I am missing? Thx for your help

Originally Posted by jjwballer

Ok, that's strange. When I compile the code it only shows words 702-1000, on the actually screen...is there just something I am missing? Thx for your help

Yeah... it's probably scrolling off the top of the screen.

Maybe the other words scrolled off the screen too fast?

Add:

Code:

if((i%100)==0)
  getchar();

inside the (outer) for loop, to see

Thanks guys, that worked.