hi all
i was just wondering if there is a way to point to a specific part of the argv structure
this is my barrier at the moment as i am reading in multiple files and i cannot write them to anything as i do not know how to point to the last part in argv
help is much appreciated
kind regards
Are you trying to get the contents of argv? Then argv[1]....argv[n] should be strings containing the parameters passed to the program. argv[0] is always the program name.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
my only issue is that there are multiple inputs so i dont know where the last input will be as that is the main one as it is the new file's name
in other words i would like to select the last input where there are multiple inputs and nobody knows how many inputs there will be
regards
Last edited by aadil7; 12-04-2010 at 02:10 PM. Reason: better description
What are you talking about? I don't understand what these inputs are? Are you talking about program PARAMETERS?
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
argc tells you how many argv arguments there are... so you want argv[argc-1]...Originally Posted by aadil7
hi thanks i think this would work because i am using argc but i had just not tough of that yet...
what would i do though if i need to use the last input as argc - 1 would take into consideration all the other inputs.
how would i also put it together as the user will specify input files which will be read and written to an output file named and created by the user.
i know what i am meant to be using and how to go about it, its just that i dont understand how i will use the last inputted name from argv and make that into a file.
kind regards
You asked how to get the last argument... I told you how.
If you need to make use of all arguments, you're going to have to cycle through them in a loop.
thanks i appreciate your help but there must be a quicker more efficient way then cycling through in a loop!
any ideas?
It's easy:
Code:#include <stdio.h> int main(int argc,char**argv) { while( argc-- ) puts(*argv++); return 0; }
Tell you what... write some code, get it working as far as you can... if you get stuck I'm sure several of us will jump in to help and offer advice. It's a local policy that we don't just hand people code... you need to show an effort first.
Shouldn't that be
argc only tells you how many elements are in the argv array, it doesn't tell you how many characters there are. Moroever, if you're planning to use argv again, you don't want to destroy argc or the pointer values for argv.Code:puts (argv[argc]);
i am fully behind hard work and writing your own code as getting someone else to do it is pointless
i am not faulting what you are saying but ive been thinking about this all day and have tried experimenting with code and have tried many different things.
i have always said this will be my last of all resorts and now it has come down to that!
Well this will teach you an important lesson then. DON'T LEAVE THINGS UNTIL THE LAST MINUTE. You could have asked these questions the day before or the day before that but you didn't.
Nobody here is going to do your homework for you. It's unethical, unprofessional and a waste of your time as well as ours. It simply doesn't do anything other than lie to yourself.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
could someone please explain to me what the code is doing
puts (argv[argc])
seems like to me when argv is mentioned it is just reffering back to argc
Have you tried google-ing puts?
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
