Thread: What is the error??

My problem is this.

First I need to read a single integer type digit from the keyboard.

Then I need to print that digit in character form.ie. if I entered 1 ,I need to get the character constant '1' as output.

In the second case I need to read a character from keyboard .If it is any one of characters 0 - 1, it will printed in the decimal form.
ie. if I enter character 1 , I need to get decimal value 1 as output.

The program is simple but I dont get correct output.
ie. I got output of first case .
In the second case I 'm not getting any output.ie program doesn't stops.
I checked whether there is an infinite loop by putting a printf() statement .
But there is no infinite loop.
Then what is my problem.

Code is this:

Code:

#include<stdio.h>

main()
{       int digit , n = 0;
        char ch;
        printf("ENTER DIGIT:");
        scanf("%d",&digit);

         for( ch = 48;n < digit;++n , ch++ );
         printf("ENTERED DIGIT IS  %c \n",ch);

         printf("NOW ENTER A CHARACTER, IF IT IS A DIGIT THAT DIGIT IS PRINTED IN DECIMAL FORM:");
         scanf(" %c ",&ch);

         for( digit = 0  ; digit < ch - 48 ; digit++ );         
         printf("ENTERED CHARACTER  IS  %d \n",digit);

}

OS Linux
compiler g++