Thread: Problem uder LINUX (gcc) and same code work at Windows (DevC++)

I have this code:

Code:

#include <stdio.h>

main()
    {

    int a,b,c;
    int *pa,*pb,*pc;

    a = 10;
    pa = &a;

    printf("Value of a=%d, b=%d, c=%d\n",a,b,c);
    printf("Address of a, b, c are %d %d %d\n",&a,&b,&c);

    pb = &b;
    *pb = *pa;

    printf("Values of a=%d, b=%d, c=%d\n",a,b,c);
    printf("Address of a, b, c are %d %d %d\n",&a,&b,&c);

    *(--pb) = *pb;

    printf("Values of a=%d, b=%d, c=%d\n",a,b,c);
    printf("Address of a, b, c areu %d %d %d\n",&a,&b,&c);

    }

This above code on Widows (DevC++) work, with only one code more on end [system("PAUSE")] to stop program before exit.

If I tray to compile this code at Linux (gcc -o address address.c) I get list of errors.

Code:

adresa.c: In function ‘main’:
adresa.c:13: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int *’
adresa.c:13: warning: format ‘%d’ expects type ‘int’, but argument 3 has type ‘int *’
adresa.c:13: warning: format ‘%d’ expects type ‘int’, but argument 4 has type ‘int *’
adresa.c:19: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int *’
adresa.c:19: warning: format ‘%d’ expects type ‘int’, but argument 3 has type ‘int *’
adresa.c:19: warning: format ‘%d’ expects type ‘int’, but argument 4 has type ‘int *’
adresa.c:24: warning: format ‘%d’ expects type ‘int’, but argument 2 has type ‘int *’
adresa.c:24: warning: format ‘%d’ expects type ‘int’, but argument 3 has type ‘int *’
adresa.c:24: warning: format ‘%d’ expects type ‘int’, but argument 4 has type ‘int *’

Why is this happening and how to resolve this.

Take a look at the formatting strings for printf() ... I don't think you want %d to print an address.

ADD to orginal post

I have gcc --version

gcc (Ubuntu 4.4.3-4ubuntu5) 4.4.3 ....

I tray to use %f, and %lo but errors are not resolved
What to use insted %d

sizeof(int) = 4
If I'm on right this is mean 2^31 - that number I can put in INT

If I use %p instead of %d I get my address

but

How this work on Windows with %d and on Linux no accept %d

my address have format: 0xbfe2ea54
this is hexadecimal

can I use than %x or %X
or can I transform hexadecimal address to decimal or binary type.