Thread: hexadecimal numbers

yeah i cud that... but it shud work fine with the method i have used too. there are errors being generated with that pointer can u pl address that

it will be easy for us to help you if you tell us about errors
please specify what are they

1.

Code:

low_up(&temp);

generates and error " cannot convert int[4] * to int" and "type mismatch in parameter 1"

2.

Code:

else
		printf("this is not a hexadeimal number");

generates a misplaced else error.

Code:

#include<stdio.h>
#include<conio.h>
#include<math.h>
void low_up(int);
void main()
{
	char ch[4];
	int temp[4],i;
	clrscr();
	printf("Enter a hexadecimal number");
	for(i=0;i<4;i++)
	{
		scanf("%c", &ch[i]);
		temp[i]=ch[i];
	}
	if((ch[i]>='a' && ch[i]<='f')||(ch[i]>='A' && ch[i]<='F'))
	{
		printf("This is a hexadecimal number");
	}
	low_up(&temp);
	for(i=0;i<4;i++)
		printf("%d\n", temp[i]);
	else // where is it's if ?
		printf("this is not a hexadeimal number");
	getch();

}
void low_up(int *j)
{
	int k;
	for(k=0;k<4;k++)
	{
		if(*j>=97 && *j<=102)
			*j=*j - 32;
		else if(*j>=65 && *j<=70)
			*j=*j + 32;
		j++;
	}
	for(i=0;i<4;i++)
	{
		printf("%c", *j);
                j++;
	}
	
}

in low_up you are passing an integer pointer(array pointer)
name of an array itself represents it's base address, so no need to use & while calling

here is the code but don't copy as it is! I am posting the complete code just you to understand how flag can be used (assuming you don't know) and the low_up fun is from the upper post. look at the data-type of ch and temp(using int will be lengthy)

Code:

#include<stdio.h>
#include<conio.h>
#include<math.h>
void low_up(char *);
int main()
{
	char ch[4], temp[4], i, flag;

	printf("Enter a hexadecimal number : ");

	for (i = 0; i < 4; i++)
	{
		scanf("%c", &ch[i]);
		temp[i] = ch[i];
	}

	flag = 0;

	for (i = 0; i < 4; i++)
	{

		if ((ch[i] >= 'a' && ch[i] <= 'f') || (ch[i] >= 'A' && ch[i] <= 'F') || (ch[i] >= 1 && ch[i] <= 9)) ;
		{
			flag++;
		}
	}
	if (flag == 4)
	{
		printf("this is a hexadeimal number");
		low_up(ch);
		printf("\n\n");
	}
	else
	{
		printf("this is NOT a hexadeimal number");
	}
	getch();
	return 0;
}

void low_up(char *j)
{
	int k, i;

	for (k = 0; k < 4; ++k)
		j[k] = isupper(j[k]) ? tolower(j[k]) : toupper(j[k]);

	for (i = 0; i < 4; i++)
	{
		printf("%c", *j);
		j = j + 1;
	}
}

which one ??

Hello. How is the weather? We have had 2" of snow here and a bit too cold to go out, so I decided to look for a program to write.

Is this what you were trying to do?

Code:

anch -run ishex.a.c #execute source code!
Enter a hex number.
Eat
'Eat' is not hex!

anch -run ishex.a.c
Enter a hex number.
FeeD
'FeeD' is hex!

This is actually C.
I just forgot a few brackets and stuff to test this free, open-source pseudocode compiler.
Anchor | freshmeat.net converts it to C, compiles it, and even invokes tcc to compile it to memory and run it directly.

Code:

#include <stdio.h>
#include <string.h>
#define MAX_STRING 4

#ifndef stricmp
#define stricmp strcasecmp
#endif

int isHex  char *s
    static int i
    char u[MAX_STRING+1]
    if  s
        sscanf(s,"%x",&i)
        sprintf(u,"%x",i)
        if  !stricmp(s,u)
            return 1
    return 0

int main  void
    char s[MAX_STRING+1]
    char fmt[10]
    sprintf  fmt,"%%%is",MAX_STRING
    printf  "Enter a hex number.\n"
    scanf  fmt,&s
    printf  "'%s' is %shex!\n",s,isHex(s)?"":"not "
    return 0

Oh no python fan?