Array question

[darktemplar]

Hi! I am trying to read in a 16 digit number into an array and at the same time check and make sure it is in fact 16 digits(display an error message if it is any more or any less)

I know how to read it in as an integer and check the digits from there, but I don't know how to convert it into a array from there.

Thanks!

[Adak]

if((number < smallest 16 digit number) ||( number > largest 16 digit number))
  printf("\n Not a 16 digit number, try again\n");

That should work for a check. What's the problem with the array -- more details?

[darktemplar]

It's not really a problem, I'm just not quite sure how to do it.

Essentially I want to read in a number, say: 1234567890123456
First, I want to check the number is 16 digits long.
Then, I need it to be stored as an array, so stored in the array are the numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6

[laserlight]

You could just read it as a string and then check the string length.

[Adak]

Ok, it's base 10, so:

index assign 15
while number16 greater than 0
  assign n number16 % 10
  (which gives n the right most digit from number16)
  now divide number16 by 10, to remove that digit, and 
  assign array[index] to the value of n
  decrement index
end loop

should get it into array[0]-[15].

[darktemplar]

Ok, I'll see how that works.

Thanks both of you!

[Adak]

Good luck, you're welcome, and

Welcome to the forum, DarkTemplar!

[laserlight]

By the way, if you want to use Adak's suggestion, you should use long long or some other 64 bit integer type. Frankly, I think it is just easier to bypass that and read as a string.