Code:
* rain.c finds yearly totals, yealy average, and monthly
average for several years of rainfall data*/
#include <stdio.h>
#define MONTHS 12 //number of months in a year
#define YEARS 5 //number of years of data
int main(void)
{
//initializing rainfall data for 2000-2004
float rain[YEARS][MONTHS] =
{
{4.3,4.3,4.3,3.0,2.0,1.2,0.2,0.2,0.4,2.4,3.5,6.6},
{8.5,8.2,1.2,1.6,2.4,0.0,5.2,0.9,0.3,0.9,1.4,7.3},
{9.1,8.5,6.7,4.3,2.1,0.8,0.2,0.2,1.1,2.3,6.1,8.4},
{7.2,9.9,8.4,3.3,1.2,0.8,0.4,0.0,0.6,1.7,4.3,6.2},
{7.6,5.6,3.8,2.8,3.8,0.2,0.0,0.0,0.0,1.3,2.6,5.2}
};
int year, month;
float subtot, total;
float *pointer;
pointer = &rain[0][0];
printf(" YEAR RAINFALL (inches)\n");
for (year = 0, total = 0; year < YEARS; year++)
{ //for each year, sum the rainfall for each month
subtot = 0;
for (month = 0; month < MONTHS; month++)
subtot += *pointer++;
printf("%5d %15.1f \n", 2000 + year, subtot);
total += subtot; //total for all years
}
printf("\nThe yearly average is %.1f inches.\n\n", total/YEARS);
printf("MONTHLY AVERAGES:\n\n");
printf(" Jan Feb Mar Apr May Jun Jul Aug Sep Oct ");
printf("Nov Dec\n");
for (month = 0; month < MONTHS; month++)
{ //for each month sum rainfall over the years
subtot = 0;
for (year = 0; year < YEARS; year++)
subtot += *pointer++;
printf("%4.1f ", subtot/YEARS);
}
printf("\n");
getchar();
return 0;
}