Thread: array of 2 dimensional arrays

Hi,
I have a few 2 dimensional arrays that are defined as the following:

Code:

const char ONE[9][6] = {
{'_','_','_','8','_','_'},
{'_','_','8','8','_','_'},
{'_','8','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','_','_','_'},
{'_','_','_','_','_','_'}
};

I'm trying to have an array that will hold the address of each 2 dimensional arrays.
It should like that:
char WORD_TO_NUMBER[] = {ZERO,ONE,TWO,THREE,FOUR};
so if I type WORD_TO_NUMBER[1] it will return the 2 dimensional array ONE.
but I cant seem to sort it out.
Id be grateful if someone could help me

Code:

#include <stdio.h>

const char ONE[9][6] = {
{'_','_','_','8','_','_'},
{'_','_','8','8','_','_'},
{'_','8','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','_','_','_'},
{'_','_','_','_','_','_'}
};
const char TWO[9][6] = {
{'2','2','_','8','_','_'},
{'2','_','8','8','_','_'},
{'_','8','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','8','_','_'},
{'_','_','_','_','_','_'},
{'_','_','_','_','_','_'}
};
typedef const char (*foo)[9][6];
// foo is a type, which is a pointer to array[9][6] of const char

void func ( foo arr ) {
  int   r, c;
  for ( r = 0 ; r < 9 ; r++ ) {
    for ( c = 0 ; c < 6 ; c++ ) {
      printf("%c", (*arr)[r][c]);
    }
    printf("\n");
  }
}
int main()
{
  foo all[] = {
    &ONE,
    &TWO
  };
  func(all[1]);
  return 0;
}

The sanity way out is to create a typedef which is the pointer to your arrays.

Without this, you end up with a mass of ()[]* every time you want to reference the type.