What's the problem?Code:#include <stdio.h> int main(void) { int iVar; //line 1 iVar = 20; //line 2 ++iVar; //line 3 printf( "\niVar : %d\n", iVar ); // line 4 iVar--; // line 5 printf( "\niVar : %d\n", iVar ); // line 6 iVar + ++iVar--; //line 7 printf( "\niVar : %d\n", iVar ); // line 8 ++( iVar + iVar ); // line 9 printf( "\niVar : %d\n", iVar ); // line 10 return 0; // line 11 }
What exactly are you trying to do with these two statements?
Code:iVar + ++iVar--;The error message is basically saying that you are trying to increment something that cannot be assigned to, e.g., it is the temporary that resulted from another operation.Code:++( iVar + iVar );
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
This code is pretty much simple arithmetic since my teacher is trying to teach us how to use operators. I don't get why it doesn't add together... Do those statements not work at all?
They do not work because the increment and decrement operators change the value of their operands. Hence, it is futile to try and use them on things that cannot change, including the result of operations like addition. It is akin to adding 3 and 4 to get 7, adding 1, and then trying to assign 8 to 7.
Look up a C++ Reference and learn How To Ask Questions The Smart Way
That really helps, thanks.
