Question

[jberg]

I sit around as an innocent newcomer to the world of programming, scrounging around on your magnificent forum, looking around for code snippets that I actually might learn something from.

and then I stumble over this

int x = '\n';

Can someone please explain the occurrence of a newline in an int, or at least point me in the direction where I can read more about this phenomena?

thanks in advance.

[Adak]

Welcome to the forum, JBerg!

Char's are just small range int's. Newlines are 10 in the internal value a PC would normally use. (In a text file format for Windows, the newline expands to become two char's: a 10 (line feed), and a 13 (carriage return).

Which is funny, because I've looked all over, and can't find a carriage that needs to be returned, even on old computers - but some of the ASCII values go back to the days of the telegraph and teletype.

Google up and download an extended ASCII table - as a programmer, you will want to keep it with an icon to it, right on your desktop.

[jberg]

Thank you for the warm welcome, much appreciated

I think I'll be able to get on with my small experiment now that I have a good clue on how to unravel the mysteries of the code

[Adak]

For a bit of fun, try printing out a newline char - but as an integer:

printf("\n Newlines have the value %d on my system \n", '\n');

[ssharish2005]

And try out this simple example as well.

Note: Ascii value in '\n'
Hex - A
Dec - 10
Oct - 012

#include <stdio.h>

int main()
{
    printf("Frist Line \xANext line");
    getchar();
    return 0;
}

/* my output
Frist Line
Next line
*/

As you could see the ASCII Hex value getting converted to the NL line feed. '\x' is used specific the printf the anything following '\x' escape sequence is the ASCII hex value and then interprets as a char.

ssharish