Thread: Counting Digits & Numbers

This program is suppose to count whitespace, digits, uppercase and lowercase letters and convert them to opposites. Any ideas what's wrong here?

Code:

#include <stdio.h>

int main(void)
{
    int iochar, numdigits=0, numlower=0, numupper=0, numwhites=0;

    printf("Please enter a phrase:\n\n");
    
    while((iochar=getchar())!=EOF) 
    {
        if ((iochar=' ')||(iochar='\t')||(iochar='\n'))
        {
        numwhites++;
        putchar(iochar);
        }
        else if((iochar>='0')&&(iochar<='9')) 
        {
        numdigits++;
        putchar(iochar);
        }
        else if(('a'>=iochar)&&(iochar<='z')) 
        {
        numlower++;
        putchar(iochar-32);
        } 
        else if(('A'>=iochar)&&(iochar<='Z'))
        {
        numupper++;
        putchar(iochar);
        }
        else putchar(iochar);    
    }
    
    printf("%d white characters, %d digits, ", numwhites, numdigits);
    printf("%d lowercase have been converted to ", numlower);
    printf("uppercase and %d uppercase.\n", numupper);
    
    printf("\n");
    
    return 0;
}

What output are you getting, and how does that differ from what you expected?

It's converting everything to white space it seems and then just counts the white space. The result of all the other nums is 0.

When i compile there is also a warning w8060 - possibly incorrect assignment in function main.

Code:

if ((iochar=' ')||(iochar='\t')||(iochar='\n'))

Wow, = instead of ==

Thanks Bayint Naung!