Thread: assignment makes pointer from integer without a cast

Hello,

I'm hoping someone can explain this warning to me. I'm sure it's just something I'm not aware of!

Code:

if ((infile = fopen("/src/infile", "r")) == NULL) {
		printf("Couldn't Open File");
		exit(1);
	} else {

		/*READ CHARS INTO THE MM STORAGE*/
		char c;
		char d;

		do{
			c = fgetc(infile);
			//printf("%c\n", c);
			if(c != '\n')
			{
			d = fgetc(infile);
			MM[I_COUNTER] = c; //<---Warning Here
			I_COUNTER++;
			MM[I_COUNTER] = d; //<---Warning Here
			I_COUNTER ++;
			}
		} while((c != 'D') && (d != 'A'));

		int k = 0;
		while(k < 4){
			c = fgetc(infile);
			k++;
		}

		//RESET OUR INSTRUCTION COUNTER
		I_COUNTER = 0;
		STACK_POINTER = 240;
	}

Thanks!

Originally Posted by rogster001

it is assumed from other parts of your code that MM should have been declared as either a char pointer and then sized, or should have been declared as fixed storage like char MM[10]

Yeah, but that's where the error is, so assumptions are all off.

@ OP: Indeed, what is the declaration of MM, it's not a double pointer by any chance, is it?

It's not defined like:

Code:

char** MM;

or

Code:

char* MM[#];

Is it? Both cases are double pointers, or arrays of pointers (same thing), the bracket operator will dereference ONE, returning a pointer. It assumes if you're setting a pointer equal to a character, you're doing something wrong.

Can you copy/paste the line it is declared on?