Thread: Function with two parameters, not sure what to return

I am writing a function called triagle that accepts two parameters 1) the length of a isosceles right triangle and 2) the letter to print. It should print like this

LLLLL
LLLL
LLL
LL
L

Here is what I have so far. I am not sure what I need to call to get the main to read in my function.

Code:

#include <stdio.h>

int triangle(int length, int letter)
{ 
	int i, j;
	for(i = 1; i <= length; i++);
	{	
		for(j = 1; j <=length; j++);
	}
	return j;

}

int main (void)
{
	int length;
	int letter;

	printf("enter the length of a isoceles triangle: \n");
	scanf("%d", &length);

	printf("enter a letter: \n");
	scanf("%d", &letter);

	printf("%d\n", triangle(length, letter));

	return 0;
}

sorry if the spacing and alignment are off

I think you would do better to put your printf() statement in your triangle function, and make your triangle function not return any value, by declaring it as returning void.

Any idea why this wont work?

Code:

#include <stdio.h>

int main(void)

{	
	int i, j, size;
	char letter;

	printf("Please enter a size:\n");
	scanf("%d", &size);

	printf("Please enter a letter:\n");
	scanf("%c", &letter);

	for (i = 1; i <= size; i++)
	{
		for (j = i; j <= size; j++)
			printf("%d", letter);

		printf("\n");
	}
	return 0;
}

Let me guess, your output consists of a bunch of 10?

it clears before I can enter a letter

no your right it does print all 10s

So I replaced the %d with a %c and it dumps out before I can enter a letter

So I replaced scanf("%c", &letter); with letter = getchar(); and had the same result. This seems so simple, why wont it work?

I get it now, thanks a bunch for the help Kermit. I got my program to run and its working perfectly!