Error Control in C Program

[repel89]

I have this program where I am supposed to only allow the user to input positive numbers, like 1, 56, 101 etc.

How can I implement error control for this program such that if the the user input negative numbers, alphabets, words, decimals or symbols, the program will not crash and loop itself to ask for another input.

Thanks

[kermit]

What have you tried so far?

[repel89]

Have tried if/else statements. Tried switch with break/continue also. Able to eliminate the negative numbers in error control. But the alphabets and decimals will pluck a random number from the memory.

Thanks for the quick reply

[kermit]

Perhaps I should have been a little more specific; could you post the latest code you have been working on? Also, are you familiar with the functions in <ctype.h>?

[Jamdog]

If a postive integer string can only contain the characters 0 to 9, it's easy enough to create a function to check it:

bool is_positive_number(const char *str)
{
  int i;

  /* Validate that a string exists */
  if ((!str) || (!*str)) return FALSE;

  /* Check each character in the string is on the range '0' to '9' */
  for (i=0; i<strlen(str); i++) {
    if ((*(str+i) < '0') || (*(str+i) > '9')) return FALSE;
  }
  return TRUE;
}

[repel89]

#include <stdio.h>
int main()

{
    int i;
    int k;
    int sum;
    sum=0;

    printf("Please input the number n u want to compute the sum to: ");
    scanf("%d", &k);

    if (k>0){

    for(i=1; i<=k; i++)
    sum=sum+i;

    printf("The sum to n terms is: %d", sum);
    }

    else {
    printf("Error");
    }

    return 0;
}

Have tried this so far. Not familiar with the <ctype.h> though. Lecturer finished the course on c programming in 3 weeks only.

Thanks for the help!

[repel89]

Another question. Still noob in C programming

Assuming i got a algorithm to sort the numbers in an array in ascending order. How is it possible that i can use it to identify the duplicate numbers in the array.

Thanks

[Jamdog]

Just parse the array, checking each element against the one before it.
Assuming you have your sorted array (of integers?) called myArray, and it has array_size elements:

int i;
/* Note, start at the 2nd element (i=1, not i=0) */
for (i=1; i<array_size; i++) {
  if (myArray[(i-1)] == myArray[i]) {
    /* duplicated element code here */
  }
}

[repel89]

Just parse the array, checking each element against the one before it.
Assuming you have your sorted array (of integers?) called myArray, and it has array_size elements:

int i;
/* Note, start at the 2nd element (i=1, not i=0) */
for (i=1; i<array_size; i++) {
  if (myArray[(i-1)] == myArray[i]) {
    /* duplicated element code here */
  }
}

Hmm, think i roughly get it, But still cant get my code to run