Thread: pointer as function argument

Hi, its been a long time since I've done any C, and I've forgotten how to use a pointer in a function declaration. For example I want to declare a function with two arguments, an integer, and a pointer to an integer. The pointer will be the address of the first element of an integer array, and within the function I want to parse through the array using pointer arithmetic, but I can't remember the syntax, and everything I try won't compile.

an example of the kinda thing I want to do:

Code:

void function(int *array_ptr, int x){
  for(i=0;i<x;i++){
    ans = (array_ptr+i) * 3.14;  //none of these compile
    ans = *(array_ptr+i) * 3.14;
    ans = &(array_ptr+i) * 3.14;
  }
}

These are correct:
ans = *(array_ptr+i) * 3.14;
ans = array_ptr[i] * 3.14;
However, if they don't work, you need to specify the compile errors.
You should note that neither ans nor i are declared in the function.