How can i make a program that converts Arabic Numbers to Roman Numbers. From 1-3999. Please help me.
How can i make a program that converts Arabic Numbers to Roman Numbers. From 1-3999. Please help me.
You could try searching the board.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
You'll need to know how "%" works. For example, this would work on 1-5:
n % 5 returns the remainder of n / 5.Code:switch(n % 5) { case 0: printf("V"); break; case 1: printf("I"); break; case 2: printf("II"); break; case 3: printf("III"); break; case 4: printf("IV"); break; }
Google algorithms for this, because I had to do this in Lisp or Haskell or Prolog (one of those useless languages) for my Programming Language Concepts course (I believe it was Lisp, but it was a year ago). So there's definitely algorithms out on the web, I found some just by googling it.
Just google something along the lines of:
program latin number roman
Switch statements are the best, here. Your best bet is to dissect the number and go through it piece by piece.
EDIT:
PS: Make sure you have a thorough understanding of the Roman Numeral System before hitting this up, sure, 1-20 is easy, but make sure you understand the rest pretty thoroughly, take a trip over to the roman numeral wikipedia. I knew I got tripped up by some of the higher numbers and it cost me a decent bit of time until I figured out some issues while working against the higher values.
