Thread: sscanf()-getting integer from a string

I want to extract the integer value form my file name, and there's no space between my file name
like

part1.dat or part12.dat

Code:

  char src[20] = "part12.dat";
  char dest[10];
  int *i;

  sscanf(src, "%[1-9]",  &i);
  printf("%d", *i);

could u plz correct my formatted text

why a int* ?

You could use strpbrk() to find digits and use atoi/strtol to convert to int.

Originally Posted by noobiept

why a int* ?

because the last argument of the sscanf is a pointer, anyway, the problem is not coming from there, its
from the formatted string, if i correct it , it would work fine

Originally Posted by Bayint Naung

You could use strpbrk() to find digits and use atoi/strtol to convert to int.

Negative;
strprbk...() returns a pointer to the first occurence of a character or whatever, but here
i have no idea what the integer would be

Originally Posted by saman_glorious

because the last argument of the sscanf is a pointer, anyway, the problem is not coming from there, its
from the formatted string, if i correct it , it would work fine

Nope, when you do &i, you were getting a pointer to pointer to int.

Originally Posted by hk_mp5kpdw

Maybe:

Code:

const char * str = "part346.dat";
int value;

sscanf(str,"%*[^0-9]%d",&value);
printf("%d",value);

thank u so much for ur help,
though, i guess i asked a stupid question
anyway thnks

Yet another cross-poster!