Thread: function for linked list

I have written a very simple example for Linked list....
but i guess I am doing something wrong with function call to print it...

can someone help here!

Code:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

struct node {
  int  data;              
  struct node *next;         
}

struct node* build(){
  struct node* head = NULL;
  struct node* third = NULL;
  struct node* second = NULL;
  
  head = (struct node *)malloc(sizeof(struct node));
  second = (struct node *)malloc(sizeof(struct node));
  third = (struct node *)malloc(sizeof(struct node));
  head->data = 1;
  head->next = second;
  
  second->data = 2;
  second->next = third;
  
  third->data = 3;
  third->next = NULL;
  return head;
} 

void printlist(head){
  struct node *current;
  struct node *lhead;
  current = lhead;
  if(current!= NULL)
    {
      do
	{
	  printf("%d\t",current->data);
	  current = current->next;
	} while (current!= lhead);
      printf("\n");  
    } 
  else
    printf("The list is empty\n");
  
}

int main(){
struct node *list = NULL;
 build(list);
 printlist(list);

}

thanks!

> current = lhead;


Um, I think you mean current = head;

ya...i had trieid that too...
but then i get bus error....

I guess i m writing some wrong function

You're not saving the result of the build function, the head of the list.

thanks !
i figured out later