Thread: "Switch", "int" and "char"!

Code:

#include<stdio.h>
void main(){
    unsigned char c=280;
    switch(c){
        printf("Start\t");
        case 280:printf("David Beckham\t");
        case 24: printf("Ronaldinho\t");
        default:  printf("Ronaldo\t");
        printf("End");
    }
    
}

When I run that code, the output is: Ronaldinho Ronaldo End

But I don't know how 280 --> 24?? in switch expression.

I hope some one will answer me, thanks you!

Take a "break" else the case statements fall through.

Code:

case 280: printf("David Beckham\t"); break;

You're missing the break after each case.

Code:

    switch(c){
        printf("Start\t");
        case 280:printf("David Beckham\t");
                        break;
        case 24: printf("Ronaldinho\t");
                      break;
        default:  printf("Ronaldo\t");
                      break;
        printf("End");
    }

Originally Posted by Salem

Or that 280 % 256 is 24

Limited range of data type and all that - did you even get a warning when you compiled this code?

Thanks Salem, I code in VS 2008 and no warning appeared.

char is one byte, so it cannot have the value of 280. The compiler should have complained with a warning.

Anyway, it goes to 24, because 280 is 100011000 now truncating this to one byte we have 00011000 which is 24.