Unicode with garbage chars

[Ducky]

I get garbage characters after "Hello" either i print it to the console or write it to a file.
How to print out only "Hello" ?

int main(void)
{
  
    WCHAR* buf3=L"Hello world!",buf4[32];
  
    wcsncpy(buf4, buf3,6);
    wprintf (L"%s",buf4);
    FILE * file = _wfopen(L"uni", L"w");
    fwrite(buf4, sizeof(wchar_t), wcslen( buf4 ), file);
  
    free(buf3);

    return 0;
}

[Bayint Naung]

Is it null ('\0') terminated?

[Ducky]

You dont need because it's unicode.

[Bayint Naung]

Are you sure?
Don't you need to use %ls ?

[Ducky]

Ok you got me, i had to.

I wasnt sure because in another program it worked without zeroing the end.

This is how i did it by the way.

buf4[6] = 0x000D;
buf4[7] = 0x000A;
buf4[8] = 0x0000;

Is there a simpler way to do it in Unicode?

Ps yes i need %ls thank you!

[Bayint Naung]

A simple test:

if( buf4[8] == L'\0' ) {
 printf("YES!!! I'm null terminated by luck!\n");
}

[Ducky]

Wow, awesome, so simple!

And i was searching high and low...

Thank you very much Bayint Naung!

[Elysia]

Ok you got me, i had to.

I wasnt sure because in another program it worked without zeroing the end.

This is how i did it by the way.

buf4[6] = 0x000D;
buf4[7] = 0x000A;
buf4[8] = 0x0000;

Is there a simpler way to do it in Unicode?

Ps yes i need %ls thank you!

Umm...

wcscpy(&buf4[6], L"\r\n");

?

Or if you really want

buf4[6] = L'\r';
buf4[7] = L'\n';
buf4[8] = L'\0';

You dont need because it's unicode.

How do you propose wprintf is able to know where the string ends, then?

[Ducky]

Thank you Elysia!