Thread: Casting to pointer from integer

I'm porting my code over to 64-bit and get the "casting to pointer from integer of different size" warning from:

Code:

(void *)(int)foo

I can understand it warning about a loss of information (casting down), but casting up isn't dangerous and the compiler should no more complain than had I done (long long)(int). Anyways I suppose that's compiler philosophy. What I need to know is how do I shut it up without resorting to #ifdef's?
This does not work:

Code:

(void *) (sizeof(void *) == sizeof(long long) ? (long long)foo : foo)

only other alternative I can think of is -Wno-int-to-pointer-cast

What if you cast to long long and then cast to void*? But that looks like a hack, heheh.

Originally Posted by laserlight

What if you cast to long long and then cast to void*? But that looks like a hack, heheh.

yep, I should have mentioned I don't want to anger my 32-bit build either

But I remembered reading something from opengroup.org on this, and it came back to me: intptr_t is the answer! It's an integer type with the same size as a pointer:

Code:

(void*)(intptr_t)foo

Why do you need to cast a pointer to an integer in the first place, though?