Help for letter count generating program

[$ingh]

Design a program with the following specifications:
Prompt the user for an alphabet.
Continue to prompt until a valid alphabet has been entered.
Starting with the user inputted alphabet, print every alphabet up to and including ‘z’ or ‘Z’
For example:
User enters ‘Q’: QRSTUVWXYZ
User enters ‘s’: stuvwxyz

so far I have, any help would be appreciated.

#include <stdio.h>


#define CHARACTER 26 // max size of array

char printstring (char str[]);//prototype

int main(void)

	{  
	  char i[CHARACTER]; 
	  printf("Please enter a capital or lowercase letter:");
	  printstring (i);
     printf("%c",i);

	  return (0);
	}

char printstring (char str[]);
	{
	return str;
		scanf("%c", str);
	  for(i='a';i<='z';i++){printf("%s",i);}
	  for(i='A';i<='Z';i++){printf("%s",i);}
	  getch();
	}
        //if(string[i]>='a' && string[i]<='z') word++;
        //if(string[i]>='A' && string[i]<='Z') word++;

[quzah]

char printstring (char str[]);
	{
	return str;

That first colored ; basically turns what you're trying to have as a function, into a prototype. You want to remove that.

char printstring (char str[])
	{
	return str;

And THAT line would make your function immediately end, rendering everything else in the function useless.

  for(i='a';i<='z';i++){printf("%s",i);}

%s prints a string, you probably want %c, to print a single character.


Quzah.

[LordPc]

i understand the problem, but your code is not solving it. its just printing out letters

you need to incorporate the letter the user gives you into the for loop so that you only print out part of the alphabet.

your also trying to print i which is in the main function. you either need to change what you are printing or declare i again in this new context

[$ingh]

thanks for the help guys.

Can anybody paste up a solution though?

[quzah]

No. This forum isn't here so people can do your work for you. It's here so you can post what you are stuck on, we can point out this and that, you correct your code and try again.


Quzah.

[$ingh]

I got the solution, i realized that i didnt even need arrays, thanks guys

#include <stdio.h>

int main (void)
	{
	char i;
	int rc;
	do{
	fflush (stdin);//flushes the input value on each loop
	printf("Please enter a lower case or capital letter.Only the first digit will be considered):");
	rc=scanf("%c", &i);
	if (i>='a' && i<='z') rc=1; //condition for loop
	else if (i>='A' && i<='Z') rc=1; //condition for loop
	else rc=0;// condition for loop

		}	while(rc!=1);

	if (i>='a' && i<='z') for (i=i;i<='z';i++) printf("%c", i);
	else for (i=i;i<='Z';i++) printf("%c", i);

	getch();
	}

[quzah]

You should visit the FAQ and read why fflush( stdin ) isn't guaranteed to work like you want it to. I'm not sure why you're capturing the return value of scanf if you don't actually do anything with it other than immediately overwrite it. You should turn on compiler warnings, which will let you know that you're reaching the end of a non-void function (main) without returning anything.


Quzah.