This function configures and enables /INT0 and /INT1 (External Interrupts)
// as negative edge-triggered.
what is meant by "as negative edge triggered" does it mean that wen the logic "0" it is triggered?Code:void Ext_Interrupt_Init (void) { TCON = 0x05; // /INT 0 and /INT 1 are edge triggered IT01CF = 0x32; // /INT0 active low; /INT0 on P0.2; // /INT1 active low; /INT1 on P0.3 EX0 = 1; // Enable /INT0 interrupts EX1 = 1; // Enable /INT1 interrupts }
thanks in advance =D
Negative edge triggered probably means that the interrupt is triggered when the signal that causes it transitions from high to low.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
Ok thanks alot i understand it now =D
its also called a "falling edge" which makes a bit more sense considering its going from high to low
