Thread: Strange question mark at EOF

I made a simple program that reads a file and prints the contents of the file to the output.

Code:

#include <stdio.h>

int main(int argc, char *argv[])
{
	if (!argv[1])
	{
		printf("USAGE: %s [filename]\n", argv[0]);
		return 1;
	}
	
	FILE *in = (fopen(argv[1], "r"));
	char *file;
	while (file != EOF)
	{
		file = fgetc(in);
		printf("%c", file);
	}
	printf("\n");
	return 0;
}

It prints the file contents to the output like it should, but there's a strange question mark at the end of it. I typed, ./prog foobar into the Terminal and it printed the following.

Code:

Hello World!
?

There is no question mark at the end of the foobar file. Is it printing the terminating null byte? Can someone explain this to me?

Originally Posted by MTK

BAD!!!

You cannot use a "char" because each byte in the file fills a whole "char". How do you think the EOF can be represented then? You have to use an int instead. It's filled with the values 0-255 for a byte from the file, and a -1 for EOF.

Also, you check if the file reached EOF before getting the next byte and printing it. You have to check between the reading of the byte and the printing.

OK, I made file an int and removed the asterisk. I'm not getting the same warning I was earlier, but it's still printing the question mark.

Originally Posted by MTK

Here's the correct code:

Code:

int file;
while (file = fgetc(in))
{
        putchar(file);
}

I saw your edited post, and replaced the old code with the above. It was an endless loop that printed only question marks. I got it working. This is what I used.

Code:

int file;
	while ((file = fgetc(in)) != EOF)
	{
		putchar(file);
	}

Thanks for pointing that out, MTK.

I wonder what compiler you are using.
and how could you ignore all your compiler warnings (if there is any?)