Thread: Double argument question

Code is too long to post so I will try to pose the problem in a simplified way.

I am dealing with epoch/unix time and read in these times from a file into a giant struct array. I assign these values as the data type double *time in the type definition.

I go through and find the max and min epoch time and assign it to variables max and min of type definition double.

Now, I am trying to pass this max and min into a function.

Upon passing in the function as an argument, when I print the values out to check that the right ones are passed in - they appear way different. I figure my way would be sufficient way as all I want to do is pass-by-value and not pass by the reference, since max and min are not memory locations or used as pointers and I do not care what happens to them inside the function. The function just uses their info and moves on.

Is this way not allowed?

Well :-/ I am away from my work computer so I cannot write up a quick code.

Essentially:

Code:

Headerfile:

typedef struct{
double *timeobs;
} time

int initialize(double max, double min);

----
Sourcefile - main.c:

int main(argc, argv){

// Skip the i/o routines

min = time->timeobs[0];
max = time->timeobs[n-1];

printf("%lf \n", max);

initialize(max, min);

return 0;
}
----
Sourcefile - function.c:

int initialize(double max, double min)
{

printf("%lf \n", max); // Check to see if right value was passed in

// Skip the innards of this code

return 0;

}

The first print statement then prints correctly, while the second one does not but gives me rubbish.

Well. It seems to be working now... :-/ Don't think I really did or changed anything?!?!

:sigh: