Thread: Returning count of spaces in a text

Why don't you just keep it simple?

Code:

for( count = 0; text; text++ )
{
    if( *test == ' ' )
        count++;
}

Of course you could do...

Code:

for( count = 0; strchr( text ); text++, count++ );

Or maybe...

Code:

int count( char *s )
{
    return s ? *s == ' ' ? 1 + count( s + 1 ) : 0 + count( s + 1 ) : 0;
}

That'll get you started.

Quzah.

No, and no (and no).

Edit: Yes, no (and no). I didn't use it enough. See below.


Quzah.

Originally Posted by EVOEx

Amazing :P. Three pieces of code, of which none actually works :P.

I was tired and on the way to bed.

Code:

for( count = 0; *text; text++ )
{
    if( *test == ' ' )
        count++;
}

And...

Code:

for( count = 0; strchr( text, ' ' ); text += 1+(strchr( text, ' ' )-text), count++ );

For some reason I was thinking I was updating text. Don't think while tired.

Code:

int count( char *s )
{
    return s && *s ? *s == ' ' ? 1 + count( s + 1 ) : 0 + count( s + 1 ) : 0;
}

1. Tired is bad.
2. You really should probably compile what you write.

Quzah.