Thread: Count Number of Letters in a Word

okay, here's a start:

Code:

char buffer[1000];
char *word;
size_t word_len;

printf("enter block of text, terminate with newline (<enter>):\n");
fgets(buffer, sizeof buffer, stdin);

word = strtok(buffer, " ");
while (word) 
{
    word_len = strlen(word);
    printf("\"%s\" has %d characters\n",word,word_len);
    word = strtok(NULL, " ");
}

now go forth and multiply

So you made a new account, skipped the forum guidelines, just to do this guy's homework for him?


Quzah.

lol. Quzah you are the best!

ive got this

Code:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define MAXWORD 50 //the max word we will see
#define MAXLINE 1000 //the max line we will see


//Function prototypes
void processLine(char [] , int [] );
void printTable(int []);

/**
 * Main function starts the program
 * Reads from the standard input and outputs to
 * the Standard output
 */


int main() {
    char line[MAXLINE];
    int counts[MAXWORD];

    while (fgets(line, sizeof (line), stdin) != NULL) {
        processLine(line, counts);
    }
    printTable(counts);
    return 0;
}

/**
 * Processes one line at a time
 */
void processLine(char line[MAXLINE] , int counts[MAXWORD] ) {
    char *word = strtok(line, ",.;:'\"&!? -_\n\t "; //cuts of word count at these symbols
	size_t word_len;
		while (word){
			word_len = strlen(word);
			printf("\"%s\" has %d characters\n", word, word_len);
			word = strtok(NULL, ",.;:'\"&!? -_\n\t ");
		}
  
}

/**
 *Prints the Word count table to stdout (use standard printf)
 */
void printTable(int counts[MAXWORD]) {
}

from here whats the best way to count how many times a word has 1, 2, 3, etc.... letters in it so i can print of a frequency chart like this to show how many times a one word letter appears and so forth? im thinking i have to save the number in the count array

len count
================
1 1680
2 4677
3 7263
4 6131
5 3669
6 2110
7 1700
8 824
9 527
10 245
11 137
12 50
13 20
14 9
15 2
17 1
================
average 4.01
================

And now for something completely different - code tags (read about them)

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<< !! Posting Code? Read this First !! >>

You can use an array if you know the maximum possible word length. Say no words are longer than 10 letters. Make an array of 11 elements, set it all to zero, and then increment the slot in the array that corresponds to word length:

Code:

numofwordsxlong[ wordlen ] ++;

If you don't know the maximum possible word length, you could make a list of some kind which stores two things, the word length, and the count, and run through the list. If that length isn't in the list, add a new bucket and set the count to 1 for that bucket, other wise, find the already existing one and increment its count.


Quzah.

Originally Posted by quzah

So you made a new account, skipped the forum guidelines, just to do this guy's homework for him?

i'm familiar with the rules here. just because i finally created an account doesnt mean i haven't been aware of this site for the past decade.

if you think i "did his homework" you've got a really, really low threshold of what constitutes either "doing", or what constitutes "homework"

that, or you just didnt really read his OP and apply any critical consideration of my minimalist reply.

Originally Posted by claudiu

lol. Quzah you are the best!

and you must be the offical Site Monkeyboy. Charmed.



.