how can i print a pointer?

[nullifyed]

hey, guys...
i want to print a pointer but i don' t know how...

i have o pointer " p " that shows to " A[5] ".
and A[5] = 123;

so, i want somehow to print " 123 "...using the pointer !
i though something like:

p = &A[5];
printf("A[5]: %p\n", p);

but it doesn' t work it prints the adress that the pointer shows....not the "cell-box" which i want...can somebody help me?

[Bayint Naung]

Sry probably i misread.
printf(" A[5]: %d\n", *p); // assuming A is array of int

[quzah]

What do mean "print the pointer"? Variables have two things you can get:

1. The value of that variable.
2. The address of that variable.

Which one do you really want, because that's all there is. There's a spot in memory, and what's stored there.

printf( "a[5] = %d", *p );

It looks like that's what you want, the value.


Quzah.

[Kennedy]

It is sometimes helpful to print with %x or %X so that you get your pointer locations in HEX. This is most helpful when you are working on a segmented memory model (like with Linux or on an X86).

[laserlight]

It is sometimes helpful to print with %x or %X so that you get your pointer locations in HEX. This is most helpful when you are working on a segmented memory model (like with Linux or on an X86).

The use of %p would be correct for such a purpose (except that the pointer should be casted to void*), and typically the output would be in a hexadecimal representation.

[nullifyed]

Thank you all...all i needed was the * !