Passing char as an array?

[xaykogeki]

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define SIZE 81


void display(char *pointerCheck[]);

int main(void)
{
   char str1[] = "0806509597";
   display(&str1[]);
  
}    

void display(char *pointerCheck[])
{
    
   int w = 0;
   int x = 0;
   int temporary[10];
   int y = 0;
   int finalOutput;
   char pointer[10];
   int finalCheck; 

	for (x = 1; x <= 10;x++)
	{
	   if (x == 10)
		{
		   printf("Trial goto\n");
	  	   goto baba;
		}

    	   pointer[w] = *pointerCheck[w];	
	   temporary[x] = atoi(&pointer[w]);


	   y = temporary[x] * (w + 1);
	   finalOutput += y;
   	   printf("%d\n",y);
           w++;
	   
	   baba:	
	   if(x == 10)
		{
		  finalOutput = finalOutput % 11;
		  finalCheck = atoi(&*pointerCheck[9]);
	  	 if (finalOutput == finalCheck)
	       	   {
			printf("Pokemon");
	           }
		}; 
	}
}

~Posted in another forum, but didn't get much of an idea~

Good day, I am having a problem with properly passing my str1 with the string included. Anyone can help me fix this? thanks.

[tabstop]

Currently your display function doesn't take a string, but rather an array of strings, which you then seem to believe is an array of chars. You should probably pick one and go with it.

[Salem]

Seems like half the posts are cross-posts all of a sudden
Passing a char array. - Dev Shed