Thread: A beginner level problem with char datatype

Code:

y = (char *)malloc(sizeof(char)*buff_size);

When using C, avoid typecasting the return value of the malloc call. Also, sizeof(char) is guaranteed to always be 1, thus the above could be safely reduced to:

Code:

y = malloc(buff_size);

You should also free the memory you've allocated to y at the end of your program (before the return statement):

Code:

free(y);