Thread: input in C?

Is there something wrong with my code?
I am quite confused about inputing a string and a character...

Code:

#include <stdio.h>
#include <stdlib.h>

int main () {
	int c[21];
	
	while (scanf("%c\n",c) != EOF) {

		printf("%s\n",c);
	}
        
       return 0;

}

Yes, you are scanf-ing a character in variable of type character array.

You need to do something like scanf("%c",c[i]); where i is some valid index.

try this:

Code:

int i = 0;

while(scanf("%c\n",c[i++] != EOF){
   printf("%s\n",c);
}

You definitely don't need to be EOF checking when doing stdin.

If you're trying to populate an integer array, then you'll be using %d, not %c.

Code:

for ( i = 0; i < 21; ++i )
{
      scanf ( "%d", &c[i] );
}

sorry, the code I posted was wrong...
It should be

Code:

int main () {
	char c[21];
	
	while (scanf("%c\n",c) != EOF) {

		printf("%c\n",c);
	}


}

i got a error message..
warning: format ‘%c’ expects type ‘int’, but argument 2 has type ‘char *’

Originally Posted by Dr Saucie

You definitely don't need to be EOF checking when doing stdin.

If you're trying to populate an integer array, then you'll be using %d, not %c.

Code:

for ( i = 0; i < 21; ++i )
{
      scanf ( "%d", &c[i] );
}

But I need to know when the user has done inputting....
if i dont do EOF checking, is there another way to know the user has finished inputting?

Code:

int main () {
        char c[21];
        int  i=0;
        while (scanf("%c",&c[i])!=EOF) {
                printf("%c",c[i++]);
        }
}