Thread: stuck on card game in C. any suggestions?

I'm not asking for the answer, I'm just asking to be pointed in the right direction!

I'm not going to post all the code because i just need help in one section of it:

Code:

void filldeck(card deck[52])

{

   /*fill the deck here*/
	

   return;

}

The deck needs to be saved in hex format into the array, i understand that hex value format is 0x[hex number]

the way the card will be saved is:

01000011

first 2 bits (11) will be the suit (11 = heart, 01 = spade, 10 = club, 00 = diamond)
next 4 bits (0000) will be the card number
next 1 bit (1) wil be the colour (1 = red, 0 = black)
last 1 bit (0) is blank

im aware i need the 01000011 converted to hex to be saved into the array.
based on this i need to generate a deck of 52 cards, i can write the cards hex values out on a paper (by hand), but how would i go about making the code generate it into the array?

if someone can please guide me to the right resource maybe i'd really appreicate it, ive looked everywhere can't find anything that will help

edit: I also think i should get rid of the ++ in my username :P

4 for loops?

Why are you saving the color? Every card deck I've ever seen had hearts and diamonds as RED, spades and puppy-dog-feet (clubs) are black.

Not the real answer, so I don't mind posting:

Code:

j = 0;
for (i = 1; i <=13 ; i++) {  // Working with Hearts
        deck[j++] = (1 << 6) | (i < 2) | 3;
}
for (i = 1 ; i <= 13; i++){ // Working with clubs
  ETC.

EDIT: Crap! I guess it was the real answer after all, sorry about that. I meant to change it up a bit.

EDIT 2: MK27's post showed me I had miscounted 7 -> 6. I really hate DST.

Originally Posted by ihatec++

edit: I also think i should get rid of the ++ in my username :P

No.

I'm not sure why you want to use hex values with the bit masking here, but go ahead. Here's some ideas (using decimal numbers, you can convert them yourself if you get a kick out of hex):

Code:

#include <stdio.h>
#include <string.h>

void getsuit(int n, char *suit) {
	switch (n) {
		case (0): 
			strcpy(suit,"diamonds");
			break;
		case (1): 
			strcpy(suit,"spades");
			break;
		case (2): 
			strcpy(suit,"clubs");
			break;
		case (3): 
			strcpy(suit,"hearts");
			break;
		default: break;
	}
}


int main() {
	unsigned bitflags = 0, 
		suitmask, valuemask, colorbit = 1<<6;
	char suit[16];

	suitmask = ~(~0U<<2);
	valuemask = ~((~0U<<6)+3);

	/* set hearts */
	bitflags ^= 3;
	bitflags ^= (1<<6);

	/* set jack */
	bitflags ^= (11<<2);

	/* show */
	getsuit(bitflags&suitmask,suit);
	printf ("Suit: %s\nValue: %d\nColor: %s\n",
		suit, (bitflags&valuemask)>>2, bitflags&colorbit ? "red" : "black");

	return 0;
}

I'm presuming you understand bitshifting which is why you want to do this. Anyway, ~ is "complement of", 0U is all zero, so ~0U is all ones...

There's an easier way to do this:

1. Generate a number between 1 and 52.
2. Face = number % 13.
3. Suite = number / 13.


Quzah.

Originally Posted by Kennedy

Still no good way to get the color, though.

> first 2 bits (11) will be the suit (11 = heart, 01 = spade, 10 = club, 00 = diamond)

Code:

if( card / 13 < 2 ) red else black

Gee that was tough. Or you could just do:

Code:

cardcolor = card > 26 ? black : red;

Quzah.

> > first 2 bits (11) will be the suit (11 = heart, 01 = spade, 10 = club, 00 = diamond)
What colours are suits in your decks Quzah?

Their "friend" has a much better ordering of suits (for extracting colour)
C Bit Manipulation