Thread: modf function incompatible pointer type

Hello

I want to use the modf() fucntion to split the integral en fractional parts.
But i dont know how i need to give the second parameter to the function.

Code:

int split(struct getallen *list, int **n, float **frac)
{

	int number, i;

	struct getallen *kopy;

	kopy = list;

	while(kopy != NULL)
	{
		number++;
		kopy = kopy -> next;
	}

	*n = (int *) malloc (number * sizeof(int));
	*frac = (float *) malloc (number * sizeof(float));

	kopy = list;

	for (i = 0; i < number; i++)
	{
		*frac[i] =  modf(kopy -> getal, &n[i]);
	}

	return 0;
	


}

I found an example here

Thank you, i have looked at examples. But i dont know how to putt it in my excersise because i have a double pointer that is an integer

First off, modf's 2nd argument is supposed to be a floating point data type: modf - C++ Reference

Furthermore, in the context of your function, n[i] would provide the ith pointer in your series, and modf is looking for a pointer, so using the address symbol & is not necessary. But still, **n is an int and modf wants a floating point data type, so I suggest you either change **n or use a temporary variable.