Thread: Strings

I am trying to store the date in memory in form of dd/mm/yy for an assignment. And although it does what I want, it compiles with errors. Which is a problem because one of the requirements is no errors when strict ANSI/ISO compliance is on.
I am getting the error, warning:format'%11s'expects type 'char*', but argument 2 has type 'char (*)[11]'
I have already tried changing the char type and no luck

Code:

#include <stdio.h>
#include <string.h>
int main()

{

char date[11];

printf("What is the date?\n");
scanf("%11s",&date);

printf("%s",date);
return 0;

}

Help me please

is there a reason you're using %11s instead of just %s?

Yes, but I didnt count that characters properly, it is supposed to be 10. I actually want it in the form dd/mm/yyyy and if there are more than 10 characters added it will cut out the extra ones, so it doesnt mess up my form.

Since you said it's an assignment I really hate to spoon feed you the answer. Compare your scanf and printf and how you pass the char array. Should be obvious.

HINT: Remember a char is an array so if you don't have an index listed it is REFERENCING the address to the first element.

Which compiler you are using?
It compiles fine in 'Visual Studio'
with no errors

Regards,
Siddu

Originally Posted by mayday

Remember a char is an array so if you don't have an index listed it is REFERENCING the address to the first element.

I don't really understand what you mean. I am just new to this and the date thing is a tiny part of my program and is not used in any of the calculations. As for my compiler, I am using Quincy 2005.

It is compiling now without any errors. Thanks so much vart