Thread: Storing and printing an array table

This is what I'm supposed to store as an array:

236.41 382.01 529.51
959.50 300.18 946.60
362.72 250.97 950.26
3.42 65.28 789.10
165.89 735.90 187.78
944.83 995.58 412.90
894.48 183.67 787.93
47.86 933.07 667.66
851.40 138.38 680.80
764.23 266.32 24.34

So the code I currently have is:

Code:

#include <stdio.h>

int main(void)
{
int i;
double	arraysums [10] [3] = {  {236.41, 382.01, 529.51},
							    {959.50, 300.18, 946.60},
								{362.72, 250.97, 950.26},
								{    3.42,   65.28, 789.10},
								{165.89, 735.90, 187.78},
								{944.83, 995.58, 412.90},
								{894.48, 183.67, 787.93},
								{  47.86, 933.07, 667.66},
								{851.40, 138.38, 680.80},
								{764.23, 266.32,  24.34}};

							printf("%d", arraysums[10][3]);
}

This is not printing at all. I've specified which rows and columns to print, and I believe I've correctly stored the numbers in an array.
After I get it printed i'm supposed to add all the numbers in each individual column and see which column I'm sure I can achieve this by using:

Code:

for (i=0; i<11; i++); 
				sum = sum + arraysums [i][1];

But I'm not sure. This problem is killing me. XD

Some of the mistakes you have done in your program,

note one thing array will have the memory less than you allocate.For ex: arr[10] will have 0-9

* printf("%f", arraysums[9][2]);
you need to print the float or double value using %f.

* for (i=0; i<11; i++);
you put the unwanted semicolon here

Try this,

Code:

    printf("%f", arraysums[9][2]);

        for (i=0; i<10; i++)
                sum = sum + arraysums[i][1];
                printf("sum:%f",sum);

Thanks. I see I made some pretty dumb mistakes. I've only recently started using 'double' and forgot it doesnt work with %d. I've made the changes to my code, and tried yours, but I get this weird error, but firstly here's my code so far:

Code:

#include <stdio.h>

int main(void)
{
double sum = 0;
double i = 0;
double	arraysums [10] [3] = {  {236.41, 382.01, 529.51},
							    {959.50, 300.18, 946.60},
								{362.72, 250.97, 950.26},
								{  3.42,  65.28, 789.10},
								{165.89, 735.90, 187.78},
								{944.83, 995.58, 412.90},
								{894.48, 183.67, 787.93},
								{ 47.86, 933.07, 667.66},
								{851.40, 138.38, 680.80},
								{764.23, 266.32,  24.34}};

				 printf("%f", arraysums[9][2]);

       for (i=0; i<10; i++)
               * sum = sum + arraysums[i][0];
                printf("sum:%f",sum); 


}

I still cant get it to print the array, but from looking at my code, I cant see why.
And I get an error on the * part, it says that the subscript is not of integral type. What does that mean? I have declared 'sum' at the top, so I'm not sure what the program is asking for.

Actually you don't need to use the dereference operator (*) on the variable sum since it isn't a pointer, so you just want to use sum = sum + arraysums[row][col] or sum += arraysums[row][col], moreover if you want to show the sums of all columns what you just need to do is to use two nested loops like this:

for i = 0 to total columns
do sum = 0;
for j = 0 to total rows
do sum = sum + arraysums[j][i]
print the sum of the current column

plus you may want to put a return 0; at the end of your code, and use ints as array subscripts, not double, so i and j must be ints
Bye