Thread: Problem with my program...

my program has not work properly...
actually my program need to print the sorted numbers in linked list...
and my program not print a sorted numbers in linked list...
here is my code..please help me..

Code:

#include <stdio.h>
#include <stdlib.h>
# include<conio.h>
# include<malloc.h>


struct node
{ 
   int data;
   struct node *next;
};


void in_begin(struct node **,int);
void display(struct node *);
void SortAscending(void);


int iArray[4]={203,5,10,110};



void main()
{

   int i;

   printf("The original array is : ");
   for(i=0;i<4;i++)
    {
       printf("| %d |",iArray[i]);
    }

   printf("\n");


SortAscending();

}


void SortAscending()
{
   int i;
   int j;
   int temp;
   int sorted_array;
   struct node *p; 
   p=NULL;

   printf("\n");
   printf("Sorted Array");
   for(i = 0; i < 4; i++)
   {
      for(j = i+1; j < 4; j++)
      {
         if(iArray[i] > iArray[j])
         { 
            temp = iArray[i];
            iArray[i] = iArray[j];
            iArray[j] = temp;
          }
      }

   printf("| %d |",iArray[i]);
   }

   printf("\n\n");

   printf("The numbers has been sorted in Linked list like this : \n");
   for (i=0;i<4;i++)
     {
         sorted_array=iArray[i];
         in_begin(&p,sorted_array);
     }
   display(p);



}


void in_begin(struct node **q,int num)
{ 
   struct node *temp;
   if(*q==NULL)
   { 
      temp=(struct node *)malloc(sizeof(struct node));
      temp->data=num;
      temp->next=*q;
     *q=temp; /* pointing to the first node */
   }
   else
   { 
      printf("Nothing");
      getch();
      goto last;
   }
   last:
   getch();
}


void display(struct node *q)
{ 
   if(q==NULL)
   { 
      printf("\n\nEmpty Link List.Can't Display The Data");
      getch();
      goto last;
   }

   while(q!=NULL)
   { 
      printf("\n%d",q->data);
      q=q->next;
   }

   last:
   getch();
}