Hi I am trying to copy one struct to another, but I am making some minor mistake that it is not getting copied. Can someone help me fix it?
Code:#include<stdio.h> #include<stdlib.h> typedef struct { int inst_addr; }instruction; void copy_struct(instruction src,instruction dest) { dest.inst_addr = src.inst_addr; } int main() { int addr = 1000; instruction check1; instruction check2; check1.inst_addr = 10; check2.inst_addr = 50; copy_struct(check1,check2); printf("%d",check2.inst_addr); }
You just change the arguments to copy_struct function as follows.
You also do one more change in calling that function as follows.Code:void copy_struct(instruction *src,instruction *dest) { *dest=*src; }
Code:copy_struct(&check1,&check2);
Last edited by vivekraj; 03-04-2010 at 01:12 AM.
Pass the address of the structure.Then inside the function access the member using '->'.Because it is a pointer variable.
Code:#include<stdio.h> #include<stdlib.h> typedef struct { int inst_addr; }instruction; void copy_struct(instruction *src,instruction *dest) { dest->inst_addr = src->inst_addr; } int main() { int addr = 1000; instruction check1; instruction check2; check1.inst_addr = 10; check2.inst_addr = 50; copy_struct(&check1,&check2); printf("%d",check2.inst_addr); }
As vivekraj suggested, you should change the function to have pointer parameters. However, instead of just assigning pointers, you should assign what the pointers point to, i.e.,Originally Posted by arun10427
EDIT:Code:*dest = *src;
That said, this would be rather pointless since you can use it directly. A function like this will come in handy when you need to do a deep copy, e.g., you have a pointer member and you wish to copy what the pointer points to.
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Actually we have answered here
Array copying problem
