Is this you want ,
Code:
#include <stdio.h>
int main()
{
int answer;//users answer input
char opt[2];
{
printf("\nIf:");
printf("\n2 + 3 = 10\n");
printf("7 + 2 = 63\n");
printf("6 + 5 = 66\n");
printf("8 + 4 = 96\n");
}
while(1)
{
printf("\nThen:\n");
printf("\n9 + 7 = ");
scanf("%d", &answer);
if(answer==144)
{
printf("It's right\n");
break;
}
else
{
printf("Wrong ! Try again ( Y(y) / N(n)) : ");
again:
scanf("%s",opt);
if(strcmp(opt,"Y")==0||strcmp(opt,"y")==0 )
continue;
else if(strcmp(opt,"N")==0 ||strcmp(opt,"n")==0)
break;
else
printf("Invalid option (Y(y) / N(n))");
goto again;
}
}
}
Thanks