Thread: convert char array to integer number

Hello,

I am attempting to convert a number from an array of chars into a reconstructed number. For example if I have an array:

Code:

 char array[5] = {5,4,3,2,1};

How can I convert it into

Code:

 int converted = 54321;

So far I have

Code:

#include <stdio.h>

int main(int argc, char *argv[])
{
    int lc_count;
    int tmp;
    int array_mult = 1;
    int hours_array[5] = {0,1,2,3,4};   // value is 1234
    int i = 4;
    
    for(lc_count = 0; lc_count <= 5; lc_count++)
    {
                 tmp = hours_array[i] * array_mult;
                 array_mult *= 10;
                 --i;
                 tmp += tmp;
    }
    
    printf("count value is:   %d" ,tmp);               
    
    system("PAUSE");    
    return 0;
}

but the output of printf is -200000, could anyone advise on what I may be doing incorrectly here?

Thanks
Dave