Thread: Print matrice with one loop?

  1. #1
    Registered User
    Join Date
    Nov 2009

    Print matrice with one loop?

    How can I print matrix with one loop . . .

    void printMat(const int mat[][N], int n)		
    	int i, j;
    	for(i = 0; i < n; i++)
    		for(j = 0; j < N; j++)
    		printf("%3d ", mat[i][j]);

  2. #2
    C++ Witch laserlight's Avatar
    Join Date
    Oct 2003
    Why do you want to do that? It would obfuscate the clear logic, in my opinion.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
    Registered User
    Join Date
    Sep 2006
    Just use common sense:

    In a 3 x 1 matrix, how many elements are there? OK, how about a 3 x 2? a 3 x 3?

    Seeing the pattern yet?

    instead of
    for(i = 0; i < rowNum; i++)
      for(j = 0; j < colNum; j++)
         printf("%3d", matrix[i][j]);
    //You would use:
    element = rowNum x colNum;
    for(i = 0; i < (well, you know the rest, ...

  4. #4
    ATH0 quzah's Avatar
    Join Date
    Oct 2001
    for( x = 0; x < rows; x++ )
        printrow( matrix[ x ] );
    There you go.

    Hope is the first step on the road to disappointment.

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