Thread: Need Help with C Programming ASAP

I have a C programming Final Project due in a couple days. I need help on getting a few things done properly. I have some things started but I don't really know where to go from here. First things first, the project is to create a program that will emulate the iPhone game called LightPaths. I have attached the instructions file below. Ok so for what I have done already:

The part of the program I have done so far is part of the puzzle generator. I have two ways of going about it. The first way I was going about it was by creating an array that uses randomly generated number to create the array which the game will use. The code for that is:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

main()
{
    int game[8][8]={0};										//declare variables for game
    int a[24];
    int start[12];
    int end[12];
    int j, i, x, in, out, temp;
    char play;
    x = time(NULL);
    srand(x); 												//seed the random value to the time
   
    printf("\n");
    printf("\t\t     LightPaths!\n");
    printf("\t\tThe puzzle of mirrors\n\n");
    printf("\t\t Want to play? y/n: ");
    scanf("%c", &play);
    printf("\n\n");

    if(play=='y')
    {
   
        game[0][0]= 0;										//sets all 4 corner cells to 0
        game[0][7]= 0;
        game[7][0]= 0;
        game[7][7]= 0;
       
        for(j=1; j<7; j++)
        {													//insert a random value for the top row, first column, last row, and last column
            game[0][j] = (rand()%12) +1;
            game[j][0] = (rand()%12) +1;
            game[7][j] = (rand()%12) +1;
            game[j][7] = (rand()%12) +1;
        }
       
        for(j=1, i=0; j<7; j++, i++)
        {													//begins to form a new array out of all the random values 0-6
            a[i] = game[0][j];
        }
       
        for(j=1, i=6; j<7; j++, i++)
        {													//continue to form the new array out of all the random values 7-12
            a[i] = game[j][0];
        }
       
        for(j=1, i=12; j<7; j++, i++)
        {													//continue to form the new array out of all the random values 13-18
            a[i] = game[7][j];
        }
       
        for(j=1, i=18; j<7; j++, i++)
        {													//continue to form the new array out of all the random values 18-23
            a[i] = game[j][7];
        }

        for(i=0; i<24; i++)
        { 													//print the values of the new array
            printf("%d ", a[i]);
        }
        printf("\n\n\n"); 										//sort the new array to determine repeated values
        for(out=0; out<24; out++)
        {
            for(in=out+1; in<24; in++)
            {
                if(a[out]>a[in])
                {
                    temp = a[in];
                    a[in] = a[out];
                    a[out] = temp;
                }
            }
        }
       
        for(i=0; i<24; i++)
        {													//print the sorted array
            printf("%d ", a[i]);
        }
       
        for(i=0; i<8; i++)
        {													//print the game 2D array
            printf("\n\n");
                 for(j=0; j<8; j++)
                 {
                  printf("     %2d", game[i][j]);
            }
        }
        printf("\n\n");
    }
    else
        printf("\t\t   Until next time!\n\n");
       
    return 0;
   
}

If anyone can help me figure out how to make it so the array only has the numbers 1-12 repeated twice. That was the 24 boundary squares have a start and end to the 12 "beams of light". Thanks for the help in advance.

Here is a link to the game

Lightpaths 1.1

Initialize your array to zeroes.

Code:

for( x = 0; x < 12; x++ )
{
    while( array[y = rand() % 24] );
    array[y] = x;
    while( array[y = rand() % 24] );
    array[y] = x;
}

There's a lazy way to do it, assuming you want to put 1 through 12 in an array twice. It's not the most efficient way to do it, but then, I'm not the one turning it in for homework either.


Quzah.