"int (x*)[5];" Could anyone tells me what's the type of x?

[hchingwong]

"int (x*)[5];"
Is x a pointer to "int ...[]"?

[laserlight]

Is x a pointer to "int ...[]"?

Yes, x is a pointer to an int[5].

[hchingwong]

Thank you laserlight.

[laserlight]

Oh wait, I'm sorry. I misread. Actually, that should result in a compile error. I was thinking of:

int (*x)[5];

[BEN10]

Oh wait, I'm sorry. I misread.

Reading your first post, I was shocked why didn't I see this type of pointer syntax before. and was about to search the internet for it.

[hchingwong]

X seems like a pointer point to an integer array that contain 5 members.
Because complier give me an warning: "assignment from incompatible pointer type" in this case.

int (*x)[5];
int b[3];
x = &b;

And this one pass without warning.

int b[5];

This's the first time I ask a question on the forum. So,
thank you everybody.

[BEN10]

X seems like a pointer point to an integer array that contain 5 members.
Because complier give me an warning: "assignment from incompatible pointer type" in this case.

int (*x)[5];
int b[3];
x = &b;

And this one pass without warning.

int b[5];

This's the first time I ask a question on the forum. So,
thank you everybody.

int (*x)[5];

Here x is a pointer pointing to an array having 5 ints. So, when you do this

int b[3];
x=&b;

You're assigning x to an array having 3 ints which is contrary to your declaration of x. That's why you get warning.

[itCbitC]

X seems like a pointer point to an integer array that contain 5 members.
Because complier give me an warning: "assignment from incompatible pointer type" in this case.

int (*x)[5];
int b[3];
x = &b;

If you really wanted to, you could finagle something like

int (*x)[5];
int b[3];
x = (int (*)[5]) &b;

[slingerland3g]

Identifier Type-- int

Name/Pointer--------- (x*) /*Can be a name or pointer to said type( this is needed to help set up the compiler to set up memory constraints */

Space/Memory used -------------[5] /* how much memory should the compiler set aside. If not initialized, then this must be assigned later or malloc must be used for the pointed to memory address */



Try this on for size:

typedef int (*pfunc)(void);
pfunc Foo;

Typedef