Thread: Roman Numerals

Hello,
I have an assignment to write a program in C to convert a numerical year into a Roman numeral. I have been messing with it for about a week and I'm stuck on where to start and how to go about doing it. If any one could help me get started or throw out a few idea os pseudocodes to get me on the right track I would appreciate it.
Thanks.

Write out the decimal number in terms of place-value notation ie thousandths, hundreds, tens, and units digits.
Now convert each of those constituent digits to its equivalent Roman numeral:

Year 1995 == 1000 (M) + 900 (CM) + 90 (XC) + 5 (V) --> "MCMXCV"
Year 1989 == 1000 (M) + 900 (CM) + 80 (LXXX) + 9 (IX) --> "MCMLXXXIX"

I started with this now I'm scratching my head wondering how to turn the 1's and 2' etc. into M,C,D,L,X,V, and I. I may have went at this the wrong way but I dont know. I figured I would error check the exceptions (ie IV, IX, XL, CM, etc.) later in for or do while loops. Any ideas on whether I ma going about this the right way, and maybee where to go with it so it makes sence, would greatly be appreciated.

Code:

#include <stdio.h>
#include<stdlib.h>
#include <time.h>

void main()
{
	int year; 
	int Roman;
	int M;
	int D;
	int C;
	int L;
	int X;
	int V;
	int I;
	int change[6];
			
			printf("Enter a year I'll convert it to its Roman Numeral Equivalent \n");
			scanf("%d", &year);
			
			M = year / 1000;
			change[0] = year%1000;
 			
			D = change[0] / 500;
			change[1]= change[0]%500;
			
			C = change[1] / 100;
			change[2] = change[1]%100;
			
			L = change[2] / 50;
			change[3] = change[2] % 50;
			
			X = change[3] / 10;
			change[4] = change[3] % 10;
			
			V = change[4] / 5;
			change[5] = change[4] % 5;
			
			I = change[5] / 1;
			
			
}