Counting quantity of different digits

**cowa** · 11-17-2009

What I'm doing wrong . . .
I need to count quantity of different digits in number
for example 321123 : and output i want like that

There r 3 different digits in the number 321123

Code:

 while(n)
 
	   {  dif=n%10;
	   n/=10;
	   if (dif=n%10)
		   n/=10;
	   else
	   count++;
	   }
	   printf("\nThere r  ",count);
	   printf(" different digits in the number",n);

**MK27** · 11-17-2009

Code:

#include <stdio.h>

int main() {
	int n=321123, copy = n, r, counts[10] = {0}, digits = 0;
	while (copy) {
		r = copy%10;
		counts[r]++;
		copy /= 10;
	}

	for (r=0;r<10;r++) {
		if (counts[r]) {
			printf("%d %d's\n",counts[r],r);
			digits++;
		}
	}

	printf("%d contains %d different digits.\n",n,digits);
	return 0;
}

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