help with char array.

[sup_stephen]

I have a string of numbers that I want to work on as a string.

#include <stdio.h>
#include <string.h>
int main()
{
	
	char  num[]= "9781552859544";
	int i;
	for (; i<12; i++)
	{
		
		
		printf("%s", num[i]);
		
		
	}
	return 0;
}

I basically want it to print out each number in turn until it reaches 12 characters, so that I can implement the actual next step.

However, it's telling me that this array of chars has a type of int and %s expects type char * why is this?

[RockyMarrone]

The problem is that your value of i is not initialized and thatz why it is takin garbage value

initialize i with 0

	char  num[]= "9781552859544";
	int i; // i = 0;

[sup_stephen]

I did initialize i. Just to be safe, I even set it to zero just now after your post, still got the error.

#include <stdio.h>
#include <string.h>
int main()
{
	
	char  num[]= "9781552859544";
	int i=0;
	for (; i<12; i++)
	{
		
		
		printf("%s", num[i]);
		
		
	}
	return 0;
}

[laserlight]

Why exactly are you trying to print a character as a string? Perhaps you would like to use %c instead of %s.

[RockyMarrone]

I did initialize i. Just to be safe, I even set it to zero just now after your post, still got the error.

#include <stdio.h>
#include <string.h>
int main()
{
	
	char  num[]= "9781552859544";
	int i=0;
	for (; i<12; i++)
	{
		
		
		printf("%s", num[i]);
		
		
	}
	return 0;
}

your modified code

#include <stdio.h>
#include <string.h>
int main()
{
	
	char  num[]= "9781552859544";
	int i=0;
	for (; i<12; i++)
	{
		
		
		printf("%c", num[i]);
		
		
	}
	return 0;