can you solve this per

[nkrao123@gmail.]

while executing below programs i getting same output .anyone can help me?

#include<stdio.h>
int main()
{
char ch='-1';
printf("%d \n",ch);
return 0;
}

#include<stdio.h>
int main()
{
char ch='-1';
printf("%d \n",ch);
return 0;
}

i getting output as 49 in both programs . i look for your suggestions

[Adak]

go to:

Commercial interests have taken over asciitables.com, but google ascii and d/l a table.

A 1 does not have the value of 1 inside your computer. It has the value of 1 only after you specify that it is a number. Same with char's.

[nkrao123@gmail.]

hi adak,

actuvally is showing same output (49) for char ch="-1" and char ch="1". thats y i little bit consfusing.can u give explanation on this?

[quzah]

Both programs are identical. Why would you expect to get different output between the two? You should compile with warnings on. '-1' isn't a single character.


Quzah.

[nkrao123@gmail.]

hi quzah,

ya i understnd your point .

from above conversion i understnd below point

so if i give '-1' , it compiling with waring and it take right hand side value '1' as a input.

thats why it showing asci value of charcter '1'=49 .

so when i give char ch='-1' or char ch='ab' , compiler compile with warning and it taken values on right hand side value ('1' ,'b').

am i right