Thread: C program output doubt

Friends,

I am doing K&R book problem 1.6 in exercise

Code:

#include <stdio.h>

main()
{
      int c;
      while(c=(getchar() != EOF))
       {
            printf("%d\n",c);
        }
            printf("on pressing ^d output is %d\n",c);
}

So C should get 0 or 1 depending on input is any character or EOF.

On executing this program in GCC, I get the following output:
> ./a.out
d
1
1


2
1
1

On pressing ctrl d, I get
0

But I am not getting why 1 is getting printed Twice instead of only ONE time?

Any answers?
Thanks
Saurav

Well you actually typed "d\n2\n^D\n" at different points in the execution. If you count the characters you typed it makes sense.

Originally Posted by whiteflags

Well you actually typed "d\n2\n^D\n" at different points in the execution. If you count the characters you typed it makes sense.

So <ENTER> is taken as an input I assume?

Thx
Saurav

Originally Posted by BEN10

Yes "ENTER" is taken as an input, which is nothing but '\n' character, so you're getting the first number for the "actual" character and the second for the "ENTER" you've pressed.

Thanks !!.

Please do forgive my ignorance, I realized your solution soon after asking the question.