Thread: How to display output using puchar() only ???

Hello ,

Here is my code. I revise it but why the putchar() can only display one character only ??

Please see the last part of the code .

Code:

#include<stdio.h>

main()
{

 int i,j,ch,decimal,count,search;
 
 int temp;

 int hex[10];
 int number[10];

 i=0;
 count=0;
 decimal=0;
 
 printf("Please enter your input in decimal form: ");
 ch = getchar();
 
 while(ch != '\n')
    {
        if('0' <= ch && ch <= '9')
         {
          decimal = decimal * 10;
          decimal = decimal + (ch - '0');
         }
      ch = getchar();
    }

 printf("Input? %d\n",decimal);

 while(decimal != 0)
    {
     hex[i] = decimal%16;
     decimal= decimal/16;
     printf("remainder is %d\n",hex[i]);
     printf("after divided is %d\n",decimal);
     i++;
     count++;
	}
	
   i=i-1;		
  for(j=0; j < count; j++)
     {
      number[j]=hex[i];
	  i--;
	  printf("number[%d] is %c\n",j, number[j]);
     }	
  printf("\n");
  for(j=0; j < count; j++)
  {
   if(number[j]==0) {putchar('0');}
   else if(number[j]==1) {putchar('1');}
   else if(number[j]==2) {putchar('2');}
   else if(number[j]==3) {putchar('3');}
   else if(number[j]==4) {putchar('4');}
   else if(number[j]==5) {putchar('5');}
   else if(number[j]==6) {putchar('6');}
   else if(number[j]==7) {putchar('7');}
   else if(number[j]==8) {putchar('8');}
   else if(number[j]==9) {putchar('9');}
   else if(number[j]==10) {putchar('A');}
   else if(number[j]==11) {putchar('B');}
   else if(number[j]==12) {putchar('C');}
   else if(number[j]==13) {putchar('D');}
   else if(number[j]==14) {putchar('E');}
   else if(number[j]==15) {putchar('F');}
   j++;
   putchar('\n');
  } 
 
}