Thread: wizzard...(!)

I have this:

Code:

#include <stdio.h>

main()
{

                 int d,choice;


		printf("gIVE 1 or 2 or 3 or 4 or 5 \n ");
		
		do{	
			scanf("%d",&choice);
			
			
			if(choice!=1 && choice!=2 && choice!=3 && choice!=4 && choice!=5)
				printf("Plz, becareful ");

		}while(choice!=1 && choice!=2 && choice!=3 && choice!=4 && choice!=5);

}

if i give an integer (7, 56,8..), it prints the message and it's waiting for a new entry. OK
if i give a character, it prints the message continuesly! why????????

thx!

The character takes the newline that scanf() leaves behind and says "I've got my char", and keeps on looping.

it's always best to pull off the left over newline, as soon as possible (or as you need to if you know the in's and out's of scanf().

add:
somevariable = getchar() ready after the scanf() and you'll see the difference (don't use choice as your variable, of course).

Originally Posted by Adak

The character takes the newline that scanf() leaves behind and says "I've got my char", and keeps on looping.

it's always best to pull off the left over newline, as soon as possible (or as you need to if you know the in's and out's of scanf().

add:
somevariable = getchar() ready after the scanf() and you'll see the difference (don't use choice as your variable, of course).

ok...

but it prints the message many time, as the characters i give.

for example
i give sdf
it prints the message 3 times...

can i avoid this?

You lost me.

Do you want to get a string of char's or a number, or ??

for a string, use: scanf("%s", someCharArrayName)

Before you use scanf() for a char, or for a string, you should have a clean keyboard buffer. for numbers, it won't matter - scanf() skips over "whitespace" when it's looking for a number.

not true for char's or strings, though.

I just want to ensure, that the user will able to give only these entries : 1 or 2 or 3 or 4 or 5.

Any other entry, is not acceptable.

try this, it is a little bit shorter

Code:

if( (choice <= 0) || (choice > 5) )

and what is

Code:

int d

for?

Planning for the future, no doubt.

exaclty!!!

somevariable = getchar() ready after the scanf() and you'll see the difference (don't use choice as your variable, of course).

what do you mean?

i wrote this, but i have the same problem..

Code:

#include <stdio.h>

main()
{

                 int choice;


		printf("gIVE 1 or 2 or 3 or 4 or 5 \n ");
		
		do{	
			choice = getchar();
			
			choice = choice -48;
			
			
			if(choice!=1 && choice!=2 && choice!=3 && choice!=4 && choice!=5)
				printf("Plz, becareful\n ");

		}while(choice!=1 && choice!=2 && choice!=3 && choice!=4 && choice!=5);

}

Originally Posted by adak

this is what i meant:

Code:

#include <stdio.h>

main()
{
                 int choice, gar;

		printf("give 1 or 2 or 3 or 4 or 5 \n ");
		
		do{	
			
                        scanf("%d", &choice);
  			
			if(choice <1 || choice >5) {
				printf("  plz, becareful\n ");
                                gar = getchar();
                        }
		}while(choice < 1 || choice >5);

}

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