question about the array in C

[thungmail]

I want to declare an array to hold 12 month from Jan to Dec. I am coding like this

char arr[] ={
      "Jan", "Feb",
      "Mar", "Apr",
      "May", "Jun",
      "Jul", "Aug",
      "Sep", "Oct",
      "Nov", "Dec"

But i got a complaining from the compiler

error: (near initialization for `arr')

I am not quite to understand. I need some help for this. Thanks

[cpjust]

char arr[]

is declaring an array of chars, but

{
      "Jan", "Feb",
      "Mar", "Apr",
      "May", "Jun",
      "Jul", "Aug",
      "Sep", "Oct",
      "Nov", "Dec"
};

is assigning an array of const char* to your array.
You need:

const char* arr[] = {
      "Jan", "Feb",
      "Mar", "Apr",
      "May", "Jun",
      "Jul", "Aug",
      "Sep", "Oct",
      "Nov", "Dec"
};

[thungmail]

Thanks for that. To get each month from above array,I use array[i].Is there any other ways to get a month from this array. Can i use

*(arr+i)

.The compiler gives me an error for this

[nadroj]

Well we would need a lot more context/information. For example, if your using exactly that, then yes its an error because theres no semi-colon at the end (though the statement doesnt really "do" anything if its exactly that anyways). Also, what is "i"? We can assume its an integer, if your saying you can do "array[i]", presumably successfully. Are you making sure "i" is less than the length of the array? For your array of months, "i" must be between 0 and 11, inclusive. Also, what is the error message from the compiler? Or you could even post your code.

[MK27]

It SHOULD work:

#include <stdio.h>

int main(void) {
	int i;
	char *this[] = { "one", "two", "three" };
	for (i=0; i<3; i++) printf("%s\n",*(this+i));
	return 0;
}